10=16x^2+9.6

Solution for 10=16x^2+9.6 equation:

10=16x^2+9.6

We move all terms to the left:

10-(16x^2+9.6)=0

We get rid of parentheses

-16x^2-9.6+10=0

We add all the numbers together, and all the variables

-16x^2+0.4=0

a = -16; b = 0; c = +0.4;
Δ = b2-4ac
Δ = 02-4·(-16)·0.4
Δ = 25.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.6}}{2*-16}=\frac{0-\sqrt{25.6}}{-32}
=-\frac{\sqrt{}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.6}}{2*-16}=\frac{0+\sqrt{25.6}}{-32}
=\frac{\sqrt{}}{-32}
$